Anyone willing to help me out with some math Problems?
(the / sign for me means Over. Ex: 8 1/2 is 8 and one over two and the --- marks seperates the Problem Number from the actuall Problem.There are spaces between the Whole number and the Fraction, and if it isint Obvious, the X is Multiplied by. like 6 X 4 is the same as 6+6+6+6)
1.-------2 1/5 X 9 7/10 = ?
2.-------1 1/4 X 2 2/3 = ?
3.-------14 2/3 X 2 1/2 = ?
4.------- 3 3/4 X 31 1/8 = ?
5.------- 45 1/3 X 8 1/9 = ?
6.-------210 1/2 X 4 1/3
7.-------7 1/3 X 3/4 = ?
8.-------3/4 X 4 4/5 = ?
9.-------21 1/2 X 56 1/2 = ?
10.-------5 1/7 X 11 4/5 = ?
11.-------8 1/3 X 3/5 = ?
12.-------82 2/3 X 6 3/4 = ?
13.-------134 2/5 X 16 1/2 = ?
(If you could post the Anwsers to the above Questions at the bottom, thatd be great! Thank you for your time! BTW:Youd be doing me a great favor by helping. I Will make it to be worth your while...Somehow.)
15 Answers to "Anyone willing to help me out with some math Problems?"
Posted by AtheistsForJesus Jan 7th, 2013 at 5:52PM
This makes me sad. :(
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Posted by Wigglebottom Jan 7th, 2013 at 5:24PM
Are you serious?
Ok I will help you.
Find the common denominator and add up the numerator to make the improper fraction so you can then continue with the rest of the problem.
OK now you finish
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Reply by ihasCupquake Jan 7th, 2013 at 5:28PM
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Reply by MrWinstonSmith Jan 7th, 2013 at 5:46PM
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Posted by Nundochips Jan 7th, 2013 at 5:24PM
You have one cupcake !
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Posted by ChakraSolipsismMGP Jan 7th, 2013 at 6:41PM
2 1/5 = 2.2 / 9 7/10 = 9.7
= 2.2
= 9.7
X
0014
0140
0180
1800
+
= 21.34 Example # 1
Example # 2
1 1/4 = 1.25 / 2 2/3 = 2.666
= 1.25
= 2.666
X
0000000
0000300
0001200
0006000
0003000
0012000
0060000
0030000
0120000
0600000
0100000
2400000
+
= 3.3325 or 3.3325
Like (1)
Posted by MrWinstonSmith Jan 7th, 2013 at 5:44PM
I feel like im missing some catch here, because if its as easy as it looks, you shouldn't need help...
im assuming you want the answers in the same form as the questions.
1.-----213 4/10
2.-----40
3.-----220
4.-----933 3/4
5.-----3309 1/3
6.-----5473
7.-----66
8.-----72
9.-----2373
10.---2124
11.---75
12.---6696
13.---22176
They really love giving you huge numbers to work with.
Sorry it took so long, my damn computer wont let me use the calculator program, im having to do it all im my head, and ill have to check why my computer is being so stubborn tomorrow.
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Reply by MrWinstonSmith Jan 7th, 2013 at 5:48PM
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Reply by Wigglebottom Jan 7th, 2013 at 5:49PM
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Posted by Sil833 Jan 7th, 2013 at 5:43PM
First, multiply the denominator by the whole number, and that number you add to the numerator, leaving it as an improper fraction. You do this with the other one as well. Now that both of them are improper, multiply them.
#7, for ex: 7 1/3 x 3/4
22/3--- [you leave the denominator as the same # which it began as] x 3/4
66/12--- and to simplify that further, divide 66 by 12 =5.5
Hope this helps... =]
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Posted by freeed Jan 7th, 2013 at 5:35PM
You change each number to all fractions, like 21 1/2 becomes 43/2 and 56 1/2 becomes 113/2. Then you multiply top times top and bottom by bottom to get 4859/4
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Posted by SpiceZ Jan 7th, 2013 at 5:32PM
1+1=3
(someone's a few cards short of a deck!)
LOL
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Posted by 151rby Jan 7th, 2013 at 5:32PM
In each problem, first convert the term on each side of the X from a mixed number into a pure fraction. Then just multiply the numerators and the denominators. I'll do the first one as an example.
2 1/5 = 10/5 + 1/5 = 11/5
9 7/10 = 90/10 + 7/10 = 97/10
11/5 X 97/10 = (11 X 97)/(5 X 10) = 1067/50
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Posted by skinnysomehow Jan 7th, 2013 at 5:30PM
Errm, what's wrong with your calculator? just curious.
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Posted by PhilAm311 Jan 7th, 2013 at 5:27PM
I would... but I'll be the one who's doing your home work not YOU..... :O
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Reply by ihasCupquake Jan 7th, 2013 at 5:33PM
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Posted by DreamingTaoTiger Jan 7th, 2013 at 5:26PM
Skipping the practice won't make the problem go away.....it will pile up more snow in the end. I'd love to help explain a single problem to get you started but as someone already mentioned. You have ONE cupcake. Funny how that is exactly what my help costs these days :3
Like (1)
Posted by scottishboyo Jan 7th, 2013 at 5:24PM
1) If I'm just supposed to post the answer, couldn't you just plug it into a calculator? Like how are you going to show your work? Just curious before I help and it doesn't get too far.
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Posted by WizGeezer Jan 7th, 2013 at 5:23PM
lol.
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Posted by pegasuss Jan 7th, 2013 at 5:23PM
You don't have some math problems. You have some maths problems, plural.
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Reply by MrWinstonSmith Jan 7th, 2013 at 5:44PM
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Reply by pegasuss Jan 7th, 2013 at 11:29PM
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