It was mathematically proven impossible for integer values for a, b, c to satisfy aⁿ+bⁿ=cⁿ for any integer n greater than 2! What did I violate here? >.> -1³ is -1, 1³ is 1, 0³ is 0, and -1 plus 1 equals zero, so the calculation is correct. I'm sure I didn't violate Fermat's Last Theorem... only that I didn't remember one condition... are negative values for a, b, and c not allowed?

MathematicallyMindedFractal
16-17, F
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May 31, 2014
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"For any integer value of n greater than two."

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Oh, duh, I copied the wrong part. "No three positive integers a, b, and c can satisfy the equation" for yada yada yada.

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I dunno.....but reading this just made my head split open. hehehe :p

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ehhh, that wasn't simple enough. LOL :p

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so a^n+b^n=c^n is impossible? SO... the Pythagorum Theorum doesn't work... lol I can't spell tonight...

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a^2+b^2=c^ (3+4=5 at right angles) (9+16=25)

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oh... n greater than 2... ok! got you ! :D

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Irrational, my dear Watson.....

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In electronics, we call it "j". I think mathematicians call it "i".

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