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wicatcher1507 wicatcher1507 18-21, M 3 Answers Sep 23, 2009

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Quick and dirty: [change in temperature]/[change in time].This isn't calculus per se, but the beginnings of it, the calculus of finite differences.<br />
Spose T1 = 80; T2 = 100 degrees and<br />
t1 = 0; t2 = 5 minute. Then {100-80}/5 would equal 4 degrees per minute increasing [positive].

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Your calculation can be done using a differential equation, but there are not enough factors here to effectively do so.

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any rate is a change in value over a change in time. So in this case, as freeed said, the change in the temperature divided by the change in time give you an average temperature rate change. Calculus gets more interesting in deriving an instantaneous rate change.

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