Yeah they should really just drop the thing and watch it explode in the middle of Times Square.

Lets see. If it was in free fall, how high would it need to be to last 10 seconds? <br />
<br />
1/2 a * t ^2 = height, so<br />
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1/2 * 9.81 * 10^2= height<br />
<br />
1/2*9.81*100 = height<br />
9.81 * 50 = height<br />
<br />
490.5m= height.<br />
<br />
I think a half kilometer drop would be a little too hard to aim right. Also, you'd have to get the height within just a few meters, otherwise your problem is off. Then there's air resistance and all, so... yeah.

first we have to hide an a bomb in it then have all the politicians attend the event. problem solved

or have like one drop every second for 10 seconds!!! 10 explosions, 10 drops, 10 awesome crashes from like 100 stories up!! um whats m/s/s??

meters per second squared. Her number is the acceleration due to gravity. She could have simply said "free fall."

meters per second per second, the correct way to describe a constant acceleration.

it ok dude i saw it, but how can it be 'per second' twice?? if its already per second why u got the second one? sorry i really suck at math im failing algebra 2 right now :/

it's the difference between speed and accelleration. when something falls, it doesn't fall at a constant speed. it accelerates. for every seconds, the speed of a falling object increases by 9.8 m/s (ignoring friction). in the first second, it's traveling at 9.8 m/s (ignoring friction). in the second second, it's traveling at 19.6 m/s (ignoring friction). "per second twice" measures accelleration, not speed.

it's like the difference between the area of a flat object (square meters) and the volume of a 3d object (cubic meters). if you still don't get it, ask your math teacher, because that's as stupid proof as I can make it.

oh wow thx

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Then what would the tower-spear height be lengthened to?