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I Want You To Review Solid And Trig

N-dimensional Sphere Volumes

By: freeed
Written on October 20th, 2011
By: freeed
Age: 61-65 , Male
231 people have read this story

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3 responses
  • NewChrissy

    Why does your intuition tell you that the volume of an n-ball is proportional to r rather than to r^d? (Where d is the complex dimension, including the degenerate cases when the real part is a positive integer and the complex part is zero, i.e., 0, 1, 2, 3, 4, . . . , n dimensions.)



    My intuition tells me that an n-ball fits more & more efficiently into higher-dimensional spaces. And of course it converges to 0 -- that's a perfect "fit".

    Mar 28, 2012
    1 like
    • freeed

      The introduction of complex numbers/dimensions/volumes is inappropriate - this article addresses real N-spheres, not complex ones. The author, presumably more educated in math than either of us, was surprised at the result, why wouldn't I be?
      You also are slightly off as to fitting the hyperspheres. They are not placed in successively higher dimension SPACES, they are placed against the faces of successively higher dimension hypercubes - the N-spheres TOUCH the hypercube faces, a perfect fit in EVERY dimension, not better or worse. The circle inscribed in a square is a perfect fit, having non-zero area (2-volume) within and without as is the easily imaginable ball in a cube.

      Mar 28, 2012
      1 like
    • NewChrissy

      I think a key insight here is to consider how the cardinality of the number of points in an n-ball changes as the dimension increases.
      http://en.wikipedia.org/wiki/Hyperreal_numbers

      Mar 29, 2012
      1 like